传送门:Poweroj - 2912
思路分析
把图转化为矩阵,没做一次转移,相当于做了一次矩阵乘法,普通的矩阵快速幂会超时,因为是01矩阵,用bitset优化矩阵
AC代码
#include <bits/stdc++.h>
#define fi first
#define se second
#define pb push_back
#define mp make_pair
#define fun function
#define sz(x) (x).size()
#define lowbit(x) (x)&(-x)
#define all(x) (x).begin(),(x).end()
#define mem(a,b) memset(a,b,sizeof(a))
namespace FastIO {
#define BUF_SIZE 100000
#define OUT_SIZE 100000
bool IOerror=0;
inline char nc() {
static char buf[BUF_SIZE],*p1=buf+BUF_SIZE,*pend=buf+BUF_SIZE;
if(p1==pend) {
p1=buf;
pend=buf+fread(buf,1,BUF_SIZE,stdin);
if(pend==p1) {
IOerror=1;
return -1;
}
}
return *p1++;
}
inline bool blank(char ch) {
return ch==' '||ch=='\n'||ch=='\r'||ch=='\t';
}
template<class T> inline bool read(T &x) {
bool sign=0;
char ch=nc();
x=0;
for(; blank(ch); ch=nc());
if(IOerror)return false;
if(ch=='-')sign=1,ch=nc();
for(; ch>='0'&&ch<='9'; ch=nc())x=x*10+ch-'0';
if(sign)x=-x;
return true;
}
template<class T,class... U>bool read(T& h,U&... t) {
return read(h)&&read(t...);
}
#undef OUT_SIZE
#undef BUF_SIZE
};
using namespace std;
using namespace FastIO;
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
typedef long long ll;
typedef pair<int,int> pii;
typedef unsigned long long ull;
const int INF = 0x3f3f3f3f;
const int N = 515;
struct Mat {
int n;
bitset<N>r[N];
bitset<N>c[N];
Mat(int nn) {
n = nn;
for(int i=1; i<=n; i++) r[i].reset(),c[i].reset();
}
Mat operator* (const Mat B) const {
Mat res(n);
for(int i=1; i<=n; i++) {
if(r[i].count() == 0) continue;
for(int j = 1; j<=n; j++) {
int f = (r[i]&B.c[j]).any();
res.r[i][j] = f;
res.c[j][i] = f;
}
}
return res;
}
Mat pow(__int128 x){
Mat res(n),bas(n);
for(int i=1;i<=n;i++) res.r[i][i] = 1,res.c[i][i] = 1;
for(int i=1;i<=n;i++) bas.r[i] = r[i],bas.c[i] = c[i];
while(x){
if(x&1) res = res*bas;
x>>=1;
bas = bas*bas;
}
for(int i=1;i<=n;i++) r[i] = res.r[i],c[i] = res.c[i];
return res;
}
};
int main() {
#ifdef xiaofan
freopen("1.in","r",stdin);
freopen("1.out","w",stdout);
#endif
int n,s,t;
__int128 o;
read(n,s,t,o);
Mat ans(n);
int m;
read(m);
while(m--) {
int u,v;
read(u,v);
ans.r[u][v] = 1;
ans.c[v][u] = 1;
}
ans.pow(o);
if(ans.r[s][t] == 1) puts("They call me Prophet");
else puts("Remember me");
return 0;
}