传送门:洛谷 - P3690
思路分析
LCT模板题
AC代码
#include <bits/stdc++.h>
#define fi first
#define se second
#define ll long long
#define pb push_back
#define mp make_pair
#define fun function
#define sz(x) (x).size()
#define lowbit(x) (x)&(-x)
#define all(x) (x).begin(),(x).end()
#define mem(a,b) memset(a,b,sizeof(a))
namespace FastIO {
#define BUF_SIZE 100000
#define OUT_SIZE 100000
bool IOerror=0;
inline char nc() {
static char buf[BUF_SIZE],*p1=buf+BUF_SIZE,*pend=buf+BUF_SIZE;
if(p1==pend) {
p1=buf;
pend=buf+fread(buf,1,BUF_SIZE,stdin);
if(pend==p1) {
IOerror=1;
return -1;
}
}
return *p1++;
}
inline bool blank(char ch) {
return ch==' '||ch=='\n'||ch=='\r'||ch=='\t';
}
template<class T> inline bool read(T &x) {
bool sign=0;
char ch=nc();
x=0;
for(; blank(ch); ch=nc());
if(IOerror)return false;
if(ch=='-')sign=1,ch=nc();
for(; ch>='0'&&ch<='9'; ch=nc())x=x*10+ch-'0';
if(sign)x=-x;
return true;
}
template<class T,class... U>bool read(T& h,U&... t) {
return read(h)&&read(t...);
}
#undef OUT_SIZE
#undef BUF_SIZE
};
using namespace std;
using namespace FastIO;
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
const int INF = 0x3f3f3f3f;
const int N = 1e5+10;
namespace LCT {
#define fa(x) (tree[x].fa)
#define ls(x) (tree[x].ch[0])
#define rs(x) (tree[x].ch[1])
#define ident(x,f) (rs(f)==x)
#define connect(x,f,s) tree[f].ch[s]=x,tree[x].fa=f
#define reverse(x) swap(ls(x),rs(x)),tree[x].tag^=1
#define notroot(x) (ls(fa(x)) == x || rs(fa(x)) == x)
struct node {
int fa,ch[2],val,res;
bool tag;
} tree[N];
inline void pp(int x) {
tree[x].res=tree[ls(x)].res^tree[rs(x)].res^tree[x].val;
}
inline void pushdown(int x) {
if(tree[x].tag) {
if(ls(x)) reverse(ls(x));
if(rs(x)) reverse(rs(x));
}
tree[x].tag=0;
}
inline void pushall(int x) {
if(notroot(x)) pushall(fa(x));
pushdown(x);
}
inline void rotate(int x) {
int f = fa(x),ff=fa(f),fs=ident(x,f),ffs=ident(f,ff);
connect(tree[x].ch[fs^1],f,fs);
fa(x) = ff;
if(notroot(f)) tree[ff].ch[ffs] = x;
connect(f,x,fs^1);
pp(f),pp(x);
}
inline void splaying(int x) {
pushall(x);
while(notroot(x)) {
int f=fa(x),ff=fa(f);
if(notroot(f)) ident(f,ff)^ident(x,f) ? rotate(x):rotate(f);
rotate(x);
}
}
inline void access(int x) {
for(int y=0; x; x=fa(x)) {
splaying(x);
rs(x)=y;
pp(x);
y=x;
}
}
inline void mkroot(int x) {
access(x);
splaying(x);
reverse(x);
}
inline int findroot(int x) {
access(x);
splaying(x);
while(ls(x)) {
pushdown(x);
x=ls(x);
}
splaying(x);
return x;
}
inline void link(int x,int y) {
mkroot(x);
if(findroot(y)==x) return;
fa(x)=y;
}
inline void cut(int x,int y) {
mkroot(x);
if(findroot(y)!=x||fa(y)!=x||ls(y)) return;
fa(y)=rs(x)=0;
pp(x);
}
inline void split(int x,int y) {
mkroot(x);
access(y);
splaying(y);
}
#undef fa
#undef ls
#undef rs
#undef ident
#undef reverse
#undef connect
#undef notroot
};
using namespace LCT;
int main() {
#ifdef xiaofan
freopen("1.in","r",stdin);
freopen("1.out","w",stdout);
#endif
int n,m;
read(n,m);
for(int i=1; i<=n; i++) read(tree[i].val);
while(m--) {
int opt,x,y;
read(opt,x,y);
switch(opt) {
case 0:
split(x,y);
printf("%d\n",tree[y].res);
break;
case 1:
link(x,y);
break;
case 2:
cut(x,y);
break;
case 3:
splaying(x);
tree[x].val=y;
pp(x);
break;
}
}
return 0;
}