传送门:洛谷 - P2617
思路分析
同样是利用差分的性质,对于树状数组的每一个节点建立一颗权值线段树
AC代码
#include <bits/stdc++.h>
#define fi first
#define se second
#define ll long long
#define pb push_back
#define mp make_pair
#define fun function
#define sz(x) (x).size()
#define lowbit(x) (x)&(-x)
#define all(x) (x).begin(),(x).end()
#define mem(a,b) memset(a,b,sizeof(a))
namespace FastIO {
#define BUF_SIZE 100000
#define OUT_SIZE 100000
bool IOerror=0;
inline char nc() {
static char buf[BUF_SIZE],*p1=buf+BUF_SIZE,*pend=buf+BUF_SIZE;
if(p1==pend) {
p1=buf;
pend=buf+fread(buf,1,BUF_SIZE,stdin);
if(pend==p1) {
IOerror=1;
return -1;
}
}
return *p1++;
}
inline bool blank(char ch) {
return ch==' '||ch=='\n'||ch=='\r'||ch=='\t';
}
template<class T> inline bool read(T &x) {
bool sign=0;
char ch=nc();
x=0;
for(; blank(ch); ch=nc());
if(IOerror)return false;
if(ch=='-')sign=1,ch=nc();
for(; ch>='0'&&ch<='9'; ch=nc())x=x*10+ch-'0';
if(sign)x=-x;
return true;
}
template<class T,class... U>bool read(T& h,U&... t) {
return read(h)&&read(t...);
}
#undef OUT_SIZE
#undef BUF_SIZE
};
using namespace std;
using namespace FastIO;
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
const int INF = 0x3f3f3f3f;
const int N = 1e5+10;
struct node{
int sum,l,r;
}tree[N*400];
struct question{
int op,l,r,k,x,y;
}q[N];
int cnt,root[N],a[N],tot;
int len[2],tmp[2][N];
vector<int>v;
int getid(int x){
return lower_bound(all(v),x)-v.begin()+1;
}
#define ls tree[x].l
#define rs tree[x].r
void modify(int &x,int l,int r,int val,int k){
if(!x) x=++cnt;
tree[x].sum+=k;
if(l==r) return ;
int mid = l+r>>1;
if(val<=mid) modify(ls,l,mid,val,k);
else modify(rs,mid+1,r,val,k);
}
void add(int x,int k){
int val = getid(a[x]);
for(int i=x;i<N;i+=lowbit(i)) modify(root[i],1,tot,val,k);
}
int query(int l,int r,int k){
if(l==r) return v[l-1];
int sum = 0;
for(int i=1;i<=len[1];i++) sum+=tree[tree[tmp[1][i]].l].sum;
for(int i=1;i<=len[0];i++) sum-=tree[tree[tmp[0][i]].l].sum;
int mid = l+r>>1;
if(sum>=k){
for(int i=1;i<=len[0];i++) tmp[0][i] = tree[tmp[0][i]].l;
for(int i=1;i<=len[1];i++) tmp[1][i] = tree[tmp[1][i]].l;
return query(l,mid,k);
} else{
for(int i=1;i<=len[0];i++) tmp[0][i] = tree[tmp[0][i]].r;
for(int i=1;i<=len[1];i++) tmp[1][i] = tree[tmp[1][i]].r;
return query(mid+1,r,k-sum);
}
}
int get(int l,int r,int k){
len[0] = len[1] = 0;
for(int i=(l-1);i;i-=lowbit(i)) tmp[0][++len[0]] = root[i];
for(int i=r;i;i-=lowbit(i)) tmp[1][++len[1]] = root[i];
return query(1,tot,k);
}
int main() {
#ifdef xiaofan
freopen("1.in","r",stdin);
freopen("1.out","w",stdout);
#endif
int n,m;
cin>>n>>m;
for(int i=1;i<=n;i++) cin>>a[i],v.pb(a[i]);
for(int i=1;i<=m;i++){
char op;
cin>>op;
q[i].op = (op=='Q');
if(op=='Q') {
cin>>q[i].l>>q[i].r>>q[i].k;
}else{
cin>>q[i].x>>q[i].y;
v.pb(q[i].y);
}
}
sort(all(v));
v.erase(unique(all(v)),v.end());
tot = sz(v);
for(int i=1;i<=n;i++) add(i,1);
for(int i=1;i<=m;i++){
if(q[i].op){
cout<<get(q[i].l,q[i].r,q[i].k)<<endl;
}else{
add(q[i].x,-1);
a[q[i].x]=q[i].y;
add(q[i].x,1);
}
}
return 0;
}