思路分析
依然是构建虚树,然后再每棵虚树上进行贪心
设$num[x]$表示$x$的子树中未被隔断的点
- 如果$x$是关键点,那么答案加上$num[x]$$(选择子树内关键点的父亲隔断)$,然后$num[x]=1$
- 如果$x$不是关键点,且$num[x]>1$,$ans++$,$num[x]=0$
AC代码
#include <bits/stdc++.h>
#define fi first
#define se second
#define ll long long
#define pb push_back
#define mp make_pair
#define fun function
#define sz(x) (x).size()
#define lowbit(x) (x)&(-x)
#define all(x) (x).begin(),(x).end()
#define mem(a,b) memset(a,b,sizeof(a))
namespace FastIO {
#define BUF_SIZE 100000
#define OUT_SIZE 100000
bool IOerror=0;
inline char nc() {
static char buf[BUF_SIZE],*p1=buf+BUF_SIZE,*pend=buf+BUF_SIZE;
if(p1==pend) {
p1=buf;
pend=buf+fread(buf,1,BUF_SIZE,stdin);
if(pend==p1) {
IOerror=1;
return -1;
}
}
return *p1++;
}
inline bool blank(char ch) {
return ch==' '||ch=='\n'||ch=='\r'||ch=='\t';
}
template<class T> inline bool read(T &x) {
bool sign=0;
char ch=nc();
x=0;
for(; blank(ch); ch=nc());
if(IOerror)return false;
if(ch=='-')sign=1,ch=nc();
for(; ch>='0'&&ch<='9'; ch=nc())x=x*10+ch-'0';
if(sign)x=-x;
return true;
}
template<class T,class... U>bool read(T& h,U&... t) {
return read(h)&&read(t...);
}
#undef OUT_SIZE
#undef BUF_SIZE
};
using namespace std;
using namespace FastIO;
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
const int INF = 0x3f3f3f3f;
const int N = 1e5+10;
#define int long long
vector<int>e[N];
int dep[N],f[N],top[N],son[N],siz[N],dfn[N],tim;
void dfs1(int u,int fa) {
dep[u]=dep[fa]+1;
siz[u]=1;
son[u]=0;
f[u]=fa;
for(auto v:e[u]) {
if(v==fa) continue;
dfs1(v,u);
siz[u]+=siz[v];
if(siz[v]>siz[son[u]]) son[u]=v;
}
}
void dfs2(int u,int t) {
top[u]=t;
dfn[u]=++tim;
if(!son[u]) return ;
dfs2(son[u],t);
for(auto v:e[u]) {
if(v==f[u] || v==son[u]) continue;
dfs2(v,v);
}
}
int getlca(int x,int y) {
while(top[x]!=top[y]) {
if(dep[top[x]]<dep[top[y]]) swap(x,y);
x=f[top[x]];
}
if(dep[x]>dep[y]) swap(x,y);
return x;
}
vector<int>new_e[N];
int st[N],Top;
void add(int u,int v){
new_e[u].pb(v);
}
void insert(int x) {
if(Top <= 1) {
st[++Top] = x;
return ;
}
int lca = getlca(x, st[Top]);
if(lca == st[Top]) {
st[++Top] = x;
return;
}
while(Top > 1 && dfn[st[Top - 1]] >= dfn[lca]) {
add(st[Top - 1], st[Top]);
--Top;
}
if(lca != st[Top]) add(lca, st[Top]), st[Top] = lca;
st[++Top] = x;
}
int dp[N],vis[N],num[N];
int dfs(int u){
int ans=0;
for(auto v:new_e[u]){
ans+=dfs(v);
num[u]+=num[v];
}
if(vis[u]){
ans+=num[u];
num[u]=1;
}else{
if(num[u]>1){
ans++;
num[u]=0;
}
}
return ans;
}
void del(int u){
num[u]=0;
vis[u]=0;
for(auto v:new_e[u]) del(v);
new_e[u].clear();
}
signed main() {
#ifdef xiaofan
freopen("1.in","r",stdin);
freopen("1.out","w",stdout);
#endif
int n,q;
read(n);
for(int i=1; i<n; i++) {
int u,v;
read(u,v);
e[u].pb(v);
e[v].pb(u);
}
dfs1(1,0);
dfs2(1,1);
read(q);
while(q--) {
int m;
vector<int>tmp;
read(m);
for(int i=1; i<=m; i++) {
int x;
read(x);
vis[x]=1;
tmp.pb(x);
}
sort(all(tmp),[](int x,int y) {
return dfn[x]<dfn[y];
});
int flag=0;
for(auto i:tmp) if(vis[f[i]]) flag=1;
if(flag){
for(auto i:tmp) vis[i]=0;
puts("-1");
continue;
}
Top=0;
if(!vis[1]) st[++Top]=1;
for(auto i:tmp) insert(i);
while(Top>1){
add(st[Top-1],st[Top]);
--Top;
}
printf("%d\n",dfs(1));
del(1);
}
return 0;
}