传送门:CodeForces-1343F
思路分析
枚举以每一个数字为开头的可能情况
确定首数字之后,第二个也就能确定了,这样就逐渐确定了所有的
最后$n^2$枚举所有可能集合,判断时候合法
样例输入
5
6
3 2 5 6
2 4 6
3 1 3 4
2 1 3
4 1 2 4 6
5
2 2 3
2 1 2
2 1 4
2 4 5
7
3 1 2 6
4 1 3 5 6
2 1 2
3 4 5 7
6 1 2 3 4 5 6
3 1 3 6
2
2 1 2
5
2 2 5
3 2 3 5
4 2 3 4 5
5 1 2 3 4 5
样例输出
3 1 4 6 2 5
3 2 1 4 5
2 1 6 3 5 4 7
1 2
2 5 3 4 1
AC代码
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
#include <bits/stdc++.h>
#define ls x<<1
#define rs x<<1|1
#define fi first
#define se second
#define ll long long
#define pb push_back
#define mp make_pair
#define fun function
#define sz(x) (x).size()
#define lowbit(x) (x)&(-x)
#define all(x) (x).begin(),(x).end()
#define mem(a,b) memset(a,b,sizeof(a))
namespace FastIO {
#define BUF_SIZE 100000
#define OUT_SIZE 100000
bool IOerror=0;
inline char nc() {
static char buf[BUF_SIZE],*p1=buf+BUF_SIZE,*pend=buf+BUF_SIZE;
if(p1==pend) {
p1=buf;
pend=buf+fread(buf,1,BUF_SIZE,stdin);
if(pend==p1) {
IOerror=1;
return -1;
}
}
return *p1++;
}
inline bool blank(char ch) {
return ch==' '||ch=='\n'||ch=='\r'||ch=='\t';
}
template<class T> inline bool read(T &x) {
bool sign=0;
char ch=nc();
x=0;
for(; blank(ch); ch=nc());
if(IOerror)return false;
if(ch=='-')sign=1,ch=nc();
for(; ch>='0'&&ch<='9'; ch=nc())x=x*10+ch-'0';
if(sign)x=-x;
return true;
}
template<class T,class... U>bool read(T& h,U&... t) {
return read(h)&&read(t...);
}
#undef OUT_SIZE
#undef BUF_SIZE
};
using namespace std;
using namespace FastIO;
using namespace __gnu_pbds;
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
typedef tree<int, null_type, less<int>, rb_tree_tag, tree_order_statistics_node_update> rbtree;
const int INF = 0x3f3f3f3f;
int n;
vector<set<int>>s,tmp;
bool judge(vector<int>x) {
set<set<int> > all;
for(auto x:s) all.insert(x);
for(int r=1; r<n; r++) {
set<int>now;
for(int l=r; l>=0; l--) {
now.insert(x[l]);
if(all.count(now)) {
all.erase(now);
break;
}
}
}
if(!all.empty()) return false;
else return true;
}
int main() {
#ifdef xiaofan
freopen("1.in","r",stdin);
freopen("1.out","w",stdout);
#endif
int t;
read(t);
while(t--) {
read(n);
s.clear();
for(int i=1; i<=n-1; i++) {
set<int>w;
int m;
read(m);
while(m--) {
int x;
read(x);
w.insert(x);
}
s.push_back(w);
}
vector<int>ans;
for(int i=1; i<=n; i++) {
int now=i;
int ok=1;
tmp=s;
while(ans.size()<n) {
int cnt=0;
ans.push_back(now);
for(int j=0; j<n-1; j++) if(tmp[j].count(now)) tmp[j].erase(now);
for(int j=0; j<n-1; j++) if(tmp[j].size()==1) cnt++;
if(cnt!=1) {
ok=0;
break;
}
for(int j=0; j<n-1; j++) if(tmp[j].size()==1) now=*tmp[j].begin();
}
if(ans.size()==n && judge(ans)) break;
if(!ok) ans.clear();
}
for(auto x:ans) cout<<x<<" ";
cout<<endl;
}
return 0;
}