传送门:牛客 - MMset2
思路分析
先找到点集中路径最长的两个点,那么答案一定是这条路径的中点到两端的距离(len/2)
如果总长是奇数的话,取大的那边,就是向上取整
样例输入
3
1 2
1 3
1
2 2 3
样例输出
1
AC代码
#include <functional>
#include <algorithm>
#include <iostream>
#include <cstring>
#include <cstdlib>
#include <iomanip>
#include <vector>
#include <string>
#include <cstdio>
#include <chrono>
#include <random>
#include <queue>
#include <stack>
#include <cmath>
#include <map>
#include <set>
#if __cplusplus >= 201103L
#include <unordered_map>
#include <unordered_set>
#endif
#define ls x<<1
#define rs x<<1|1
#define fi first
#define se second
#define ll long long
#define pb push_back
#define mp make_pair
#define fun function
#define sz(x) x.size()
#define lowbit(x) x&(-x)
#define all(x) x.begin(),x.end()
#define mem(a,b) memset(a,b,sizeof(a))
#define IOS ios_base::sync_with_stdio(0); cin.tie(0);cout.tie(0);
using namespace std;
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
const int INF = 0x3f3f3f3f;
const int N=1e6+10;
vector<int>e[N];
int fa[N],dep[N],son[N],siz[N],top[N],a[N];
void dfs1(int u,int f) {
fa[u]=f;
dep[u]=dep[f]+1;
siz[u]=1;
int maxsize=-1;
for(auto v:e[u]) {
if(v==f)continue;
dfs1(v,u);
siz[u]+=siz[v];
if(siz[v]>maxsize) {
son[u]=v;
maxsize=siz[v];
}
}
}
void dfs2(int u,int t) {
top[u]=t;
if(!son[u])
return ;
dfs2(son[u],t);
for(auto v:e[u]) {
if(v==son[u]||v==fa[u])
continue;
dfs2(v,v);
}
}
int lca(int x,int y) {
while(top[x]!=top[y]) {
if(dep[top[x]]<dep[top[y]]) swap(x,y);
x=fa[top[x]];
}
return dep[x]>dep[y]?y:x;
}
int dis(int u,int v){
return dep[u]+dep[v]-2*dep[lca(u,v)];
}
int main() {
IOS;
#ifdef xiaofan
freopen("1.in","r",stdin);
freopen("1.out","w",stdout);
#endif
int n;
cin>>n;
for(int i=1;i<n;i++) {
int u,v;
cin>>u>>v;
e[u].push_back(v);
e[v].push_back(u);
}
int q;
dfs1(1,1);
dfs2(1,1);
cin>>q;
while(q--){
int x;
cin>>x;
for(int i=1;i<=x;i++) cin>>a[i];
int d=a[1];
for(int i=2;i<=x;i++) if(dep[a[i]]>dep[d]) d=a[i];
int ma=0;
for(int i=1;i<=x;i++) ma=max(ma,dis(a[i],d));
cout<<(ma+1)/2<<endl;
}
return 0;
}